Unique Rate quick question


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Marina Gollas 1A
Posts: 36
Joined: Fri Sep 28, 2018 12:20 am

Unique Rate quick question

Postby Marina Gollas 1A » Sat Mar 16, 2019 12:41 pm

How are we able to figure out the unique rate of the reaction if there are more than one reactants given in the equation? Since I know if there was one reactant you would divide the rate of the reaction by the coefficient of that one reactant, but what if there are more than one? Do we multiply the two coefficients together and then divide it? Thank you:)

605168557
Posts: 65
Joined: Fri Sep 28, 2018 12:18 am

Re: Unique Rate quick question

Postby 605168557 » Sat Mar 16, 2019 12:46 pm

In general for all reactions: aA --> bB + cC

The unique rate is -1/a * d[A]/dt = 1/b * d[B]/dt = 1/c * d[C]/dt

The unique rate is the same for all R & P in that 'unique' reaction

Marina Gollas 1A
Posts: 36
Joined: Fri Sep 28, 2018 12:20 am

Re: Unique Rate quick question

Postby Marina Gollas 1A » Sat Mar 16, 2019 1:20 pm

605168557 wrote:In general for all reactions: aA --> bB + cC

The unique rate is -1/a * d[A]/dt = 1/b * d[B]/dt = 1/c * d[C]/dt

The unique rate is the same for all R & P in that 'unique' reaction


Ohhhh ok so unique rates normally do not have more than one reactants then? Is that what you mean?


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