Unique rate law

[Mara Lockhart 3J]

In kinetics, what does a unique rate law mean?

[Mara Lockhart 3J]

I think I found the answer to my own question, but if anyone has additional comments, please add on!

To find the unique rate of a reaction, you take the rate (of any product or reactant) and divide by the stoichiometric coefficient of that chosen species. It does not matter what rate you choose, because there is only one average rate or unique rate of a reaction.

For example, if you have the rate of formation of H2O is 1.856 mol.L.s for the reaction H2 + 1/2O2 ----> H2O, the unique reaction rate would be (1.856mol.L.s)/(1) = 1.856 mol.L.s. So the unique retain rate is the average rate.

[Neil DSilva 1L]

You're referring to the unique average rate (not unique rate law), right? Other than that, everything else you said seems correct.

[Mara Lockhart 3J]

Whats the difference of the two? On question 14.5, the question just asked what is the unique rate of the reaction, so are they asking for the unique average rate or the unique rate law?

[Kayla Denton 1A]

If the question asks for the "rate" it just wants one number, not the rate law expression. So you'd just do the unique average rate (I guess they just omitted the word average because it was implied).

I don't think in the chapter they ever ask for the "unique rate law."

[Neil DSilva 1L]

Yeah, I didn't think the "unique rate law" was a thing, so I was just checking.