## slow step

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Baoying Li 1B
Posts: 113
Joined: Sat Aug 17, 2019 12:18 am

### slow step

Under what conditions do we only consider use the rate law of slow step as the overall rate laws? Is that always the case?

Anisha Chandra 1K
Posts: 118
Joined: Thu Jul 11, 2019 12:17 am

### Re: slow step

I think the book said something like this:
- if the slow step is the second step, the rate law for that step determines the rate law for the reaction
- if the slow step is the first step, the rate law for that step must match the rate law for the reaction

005324438
Posts: 51
Joined: Sat Aug 24, 2019 12:16 am

### Re: slow step

If it is a multi-step reaction and one is significantly slower than the other, then we will always use that step to determine the rate-law.

405268063
Posts: 102
Joined: Thu Jul 25, 2019 12:17 am

### Re: slow step

I believe that the slowest step of a multi-step reaction is the rate-determining step.

Robert Tran 1B
Posts: 118
Joined: Thu Jul 11, 2019 12:15 am

### Re: slow step

For all conditions, the slowest step determines the rate of the reaction, because the reaction can only proceed as fast as the slowest process.

Sofia Barker 2C
Posts: 101
Joined: Wed Sep 18, 2019 12:21 am

### Re: slow step

The slow step of a reaction is always the rate-determining step for an overall reaction.

Nare Nazaryan 1F
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

### Re: slow step

I think the slow step is the one that determines the rate law for the overall reaction.

Posts: 74
Joined: Fri Sep 28, 2018 12:29 am

### Re: slow step

The slow step is the one that determines the rate law

SimranSangha4I
Posts: 99
Joined: Sat Sep 14, 2019 12:17 am

### Re: slow step

The slow step would be the rate determining step, so that would be used in finding the rate-law.

Gerald Bernal1I
Posts: 102
Joined: Thu Jul 11, 2019 12:16 am

### Re: slow step

Its the rate determining step unless it does not match up with the actual rate law of the reaction.

### Who is online

Users browsing this forum: No registered users and 1 guest