7A.3


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Labiba Sardar 2A
Posts: 103
Joined: Sat Jul 20, 2019 12:15 am

7A.3

Postby Labiba Sardar 2A » Sun Mar 08, 2020 7:33 pm

The combustion reaction C2H4 (g) + 3O2 (g) --> 2CO2 (g) + 2H2O (g) has a unique rate of .44 mol.L^-1.s^-1

When finding the rate at which oxygen reacts and the rate at which water forms, why do both of these rates have positive values? Shouldn't they be opposite values since one is used up in the reaction (O2) while the other is formed (H2O)?

Nikki Razal 1L
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Re: 7A.3

Postby Nikki Razal 1L » Sun Mar 08, 2020 7:36 pm

I feel like the rates would both be positive because I think they are technically the same, just working in the opposite direction. either way, the book says that positive reaction rate is the normal convention in chemical kinetics

Kate Osborne 1H
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Joined: Fri Aug 30, 2019 12:16 am

Re: 7A.3

Postby Kate Osborne 1H » Sun Mar 08, 2020 7:37 pm

the unique rate is the same for all reactants and products in that unique reaction. so the rate at which the product forms and the reactant is used up must equal each other, so they have to have the same sign.

Emily Vainberg 1D
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Re: 7A.3

Postby Emily Vainberg 1D » Mon Mar 09, 2020 1:57 pm

For part A of this question, did you get that the rate of O2 was 1.32 moles.L-1.s-1 ?

Amy Pham 1D
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Re: 7A.3

Postby Amy Pham 1D » Mon Mar 09, 2020 2:04 pm

Emily Vainberg 1D wrote:For part A of this question, did you get that the rate of O2 was 1.32 moles.L-1.s-1 ?

Yes, this is correct! The rate of consumption of oxygen (O2) is 1.3 mols.L-1.s-1, with correct sigfigs.


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