## 7B5a

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Amy Xiao 1I
Posts: 101
Joined: Sat Jul 20, 2019 12:15 am

### 7B5a

Dinitrogen pentoxide, N2O5, decomposes by first-order kinetics with a rate constant of 3.7 x 10^-5 /s at 298 K. (a) What is the half-life (in hours) of N2O5 at 298 K?

I am somewhat confused by how the units cancel. Why are the seconds applied to ln2 (numerator) and not the 3.7x10^-5 (denominator)?
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Niharika 1H
Posts: 50
Joined: Thu Jul 25, 2019 12:16 am

### Re: 7B5a

0.693/(3.7*10^-5) = 18729.73 s
To get this in hours, we have to divide it by 3600s, to get 5.2 hours.