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### overall order

Posted: Mon Mar 09, 2020 3:43 pm
How do you calculate the overall order?

### Re: overall order

Posted: Mon Mar 09, 2020 3:47 pm
You'll have to find the order of the individual reactants then add them up

### Re: overall order

Posted: Mon Mar 09, 2020 3:48 pm
You just add up the individual orders. So if you have A + B --> C and reactant A is order 1 and reactant B is order 2, the overall order would be 3

### Re: overall order

Posted: Mon Mar 09, 2020 3:48 pm
The overall order is just the sum of all the powers of the reactants in the rate law. Such as Rate=k[A]^2[B]^1 has an overall order of 3

### Re: overall order

Posted: Mon Mar 09, 2020 5:48 pm
the overall order is equal to the sum of all the orders of the reactants. The order of each reactant is the exponential value of the reactant

### Re: overall order

Posted: Mon Mar 09, 2020 5:51 pm
to calculate the overall order of a reaction you would add the exponents of the reactants.

for example, if the rate law =k[A]2[B]1, then the overall order would be 3 (2+1)