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### 15.17

Posted: **Mon Feb 20, 2017 12:09 am**

by **Michelle_Tan_1G**

I have a question as to how to find the order of B. Knowing that C is zero order, I only compare A and B (using experiments 2 and 3, which have [A]o constant). My equation is 200^n/100 = 16/4.0. However, when I solve for n, I get a fractional number. I'm pretty sure I'm supposed to cancel 200 by using log(subscript)200. What am I doing wrong?

### Re: 15.17

Posted: **Mon Feb 20, 2017 12:15 am**

by **Chem_Mod**

THe order could be a fraction number sometime.

### Re: 15.17

Posted: **Mon Feb 20, 2017 4:59 pm**

by **Amy_Bugwadia_3I**

The order of B according to the solutions at the back of the book is 2 (the reaction is second order with respect to B). The way I solved for B is (rate of expmt. 3)/(rate of expmt. 2) = 16/4.0 = (200/100)^b. Solving for b, I got b = 2. Thus, in the rate equation, the concentration of B is raised to the power of 2 and the reaction is second order with respect to B.