Homework 15.19 c & d
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Homework 15.19 c & d
For this problem for part c, the answer in the back of the book says 2.85 x 10^12. I'm getting only 2.85 and I'm not sure where the 10^12 comes from. Also for d, the method of solving would just be plugging the appropriate numbers into rate=[A][B^2][C^2], correct?
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Re: Homework 15.19 c & d
Hello,
I also had the same problem until I realized what I forgot to do. The units of the rate constant should be (L^4)/[(mol^4)(s)]. You have to convert the initial concentrations in the experimental set of concentrations you use from mmol/L to mol/L. That will get you 2.85 x 10^12.
I also had the same problem until I realized what I forgot to do. The units of the rate constant should be (L^4)/[(mol^4)(s)]. You have to convert the initial concentrations in the experimental set of concentrations you use from mmol/L to mol/L. That will get you 2.85 x 10^12.
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Re: Homework 15.19 c & d
You could leave your units as (mmol/L*s) or (mmol/L) unless the question specifically asks you to use a certain unit then you would have to convert. You just have to be consistent with your units and you'll be fine.
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