## Using this method to solve for rate law okay?

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### Using this method to solve for rate law okay?

The integrated rate laws are derived from the following, assuming that a=1 for: -1/a d[A]/dt= k But what if we are given a reaction in which the coefficients are not 1? Do we still use the same integrated rate law or do we plug in, for example, a=2 in the equation above, and then integrate to get a modified integrated rate law?

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### Re: Using this method to solve for rate law okay?

That will change your k value