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15.15

Posted: Thu Mar 01, 2018 11:08 am
by Shannon Wasley 2J
What are the orders of the reactants for this question?

Re: 15.15

Posted: Thu Mar 01, 2018 11:41 am
by Esin Gumustekin 2J
The order of each reactant is first order. I believe this would mean that the overall reaction order is second order.

Re: 15.15

Posted: Thu Mar 01, 2018 12:12 pm
by Kelly Kiremidjian 1C
Both of the reactants are first order because their concentrations are directly proportional to the rate increase factor.

Re: 15.15

Posted: Thu Mar 01, 2018 4:35 pm
by Ammarah 2H
For clarification: If the question said that the OH- concentration doubled and the rate quadrupled, would the order with respect to OH- be second order?

Re: 15.15

Posted: Sat Mar 03, 2018 12:04 pm
by 104922499 1F
the order for both [CH3Br] and [OH-] are n=1 so the overall reaction order would be 2 because 1+1= 2

Re: 15.15  [ENDORSED]

Posted: Sat Mar 03, 2018 9:55 pm
by Jenny Cheng 2K
In general, rate = k * [A]^a * [B]^b ...
Thus, overall order = a + b + ...