Page 1 of 1
Posted: Thu Mar 01, 2018 11:08 am
What are the orders of the reactants for this question?
Posted: Thu Mar 01, 2018 11:41 am
The order of each reactant is first order. I believe this would mean that the overall reaction order is second order.
Posted: Thu Mar 01, 2018 12:12 pm
Both of the reactants are first order because their concentrations are directly proportional to the rate increase factor.
Posted: Thu Mar 01, 2018 4:35 pm
For clarification: If the question said that the OH- concentration doubled and the rate quadrupled, would the order with respect to OH- be second order?
Posted: Sat Mar 03, 2018 12:04 pm
the order for both [CH3Br] and [OH-] are n=1 so the overall reaction order would be 2 because 1+1= 2
Re: 15.15 [ENDORSED]
Posted: Sat Mar 03, 2018 9:55 pm
In general, rate = k * [A]^a * [B]^b ...
Thus, overall order = a + b + ...