15.23 & 15.29  [ENDORSED]

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Ammarah 2H
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

15.23 & 15.29

Postby Ammarah 2H » Thu Mar 01, 2018 9:04 pm

In 23 part c and 29 part a, why do we take the initial concentration of A and subtract the moles times [B]?

Samantha Kan 2L
Posts: 30
Joined: Sat Jul 22, 2017 3:00 am

Re: 15.23 & 15.29

Postby Samantha Kan 2L » Thu Mar 01, 2018 9:38 pm

You need the final mols of A, but you are given the concentration B has risen to. You first calculate the amount of mols of A that need to be used up for B to have that concentration. Then you subtract that value from the initial mols of A to find the final mols of A.

Timothy Kim 1B
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.23 & 15.29  [ENDORSED]

Postby Timothy Kim 1B » Fri Mar 02, 2018 10:26 am

I believe that in order to produce B, A has to be used up. Therefore, B uses x amount A so we subtract A initial minus x.


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