15.55 a

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Meghna2A
Posts: 32
Joined: Fri Sep 29, 2017 7:06 am

15.55 a

Postby Meghna2A » Sat Mar 03, 2018 11:31 pm

(a) For a reaction with a very large equilibrium constant, the rate constant of
the forward reaction is much larger than the rate constant of the reverse reaction. Why?

rkusampudi
Posts: 58
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.55 a

Postby rkusampudi » Sun Mar 04, 2018 12:23 am

A large equilibrium constant means that the products are favored.

Deborah Cheng 1F
Posts: 50
Joined: Thu Jul 13, 2017 3:00 am

Re: 15.55 a

Postby Deborah Cheng 1F » Sun Mar 04, 2018 7:50 am

K>1 means that products are favored, K<1 means the reactants are favored. Rate constant and equilibrium constant are proportional so when the equilibrium constant is large, rate constant of forward reaction is also large.

ConnorThomas2E
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.55 a

Postby ConnorThomas2E » Sun Mar 04, 2018 11:20 am

As said before, the rate constant is always proportional to K. Therefore, when K is very large, meaning the products are favored, you will have a large rate constant.


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