Rate Constant in Terms of B, C, D, etc.

Moderators: Chem_Mod, Chem_Admin

Kyle Sheu 1C
Posts: 87
Joined: Fri Jun 23, 2017 11:39 am

Rate Constant in Terms of B, C, D, etc.

Postby Kyle Sheu 1C » Sun Mar 04, 2018 4:08 pm

Given the reaction aA + bB --> cC + dD:

The rate constant k is often given in terms of "loss of A." How would k be different if it were given in terms of the loss of B, the gain of C, or the gain of D? How would the integrated rate laws and their graphs be different?

Anh Nguyen 2A
Posts: 36
Joined: Fri Sep 29, 2017 7:05 am
Been upvoted: 1 time

Re: Rate Constant in Terms of B, C, D, etc.

Postby Anh Nguyen 2A » Sun Mar 04, 2018 4:53 pm

k is constant and characteristic of the reaction and the temperature so it does not matter if k is given in terms of loss of A or gain of C, etc., it would always be the same.
I think that "given in the terms of loss of A" only clarifies what integrated rate law to use to find k. For example in 15.29 the reaction is of first-order and they ask the rate constant for the reaction expressed as the rate of loss of A, we then know that k is found through the first order reaction integrated rate law using [A]o and [A]. If the constant is expressed as the gain of D, then the only difference that we use the concentrations of D instead of A. The same goes for loss of B and gain of C. And k should be the same in every situations.

Return to “Method of Initial Rates (To Determine n and k)”

Who is online

Users browsing this forum: No registered users and 1 guest