### Rate Constant in Terms of B, C, D, etc.

Posted: **Sun Mar 04, 2018 4:08 pm**

by **Kyle Sheu 1C**

Given the reaction aA + bB --> cC + dD:

The rate constant k is often given in terms of "loss of A." How would k be different if it were given in terms of the loss of B, the gain of C, or the gain of D? How would the integrated rate laws and their graphs be different?

### Re: Rate Constant in Terms of B, C, D, etc.

Posted: **Sun Mar 04, 2018 4:53 pm**

by **Anh Nguyen 2A**

k is constant and characteristic of the reaction and the temperature so it does not matter if k is given in terms of loss of A or gain of C, etc., it would always be the same.

I think that "given in the terms of loss of A" only clarifies what integrated rate law to use to find k. For example in 15.29 the reaction is of first-order and they ask the rate constant for the reaction expressed as the rate of loss of A, we then know that k is found through the first order reaction integrated rate law using [A]o and [A]. If the constant is expressed as the gain of D, then the only difference that we use the concentrations of D instead of A. The same goes for loss of B and gain of C. And k should be the same in every situations.