14.19 in Book Q

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14.19 in Book Q

Postby 103978133 » Sat Mar 08, 2014 11:30 pm

In this question I didn't understand how the order for B and C is 2. The reaction is A+B+C--> PRODUCTS. I thought they were 3 because if we look at C's concentration, it tripled from experiment 3 to 4, and the initial rate also increased by 9 times from 50.8 to 457. Why is the rate law of this reaction is k(A)(B)^2(C)^2?

Posts: 314
Joined: Fri Sep 20, 2013 3:00 am

Re: 14.19 in Book Q

Postby ch1995 » Sat Mar 08, 2014 11:32 pm

When the concentration of C is tripled (while conc of A and B stays constant), the rate of reaction increases by a factor of 9:
3x = 9
x= 2

Therefore, the order of C will be 2.

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