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7A. 1 in the 7th edition

Posted: Mon Mar 04, 2019 4:33 pm
by Adams Dis 1A
What is the question trying to ask? I am extremely confused on this one.

Re: 7A. 1 in the 7th edition

Posted: Mon Mar 04, 2019 4:36 pm
by Kavvya Gupta 1H
it's similar to what Lavelle went over on Friday in lecture to where you treat it like a ratio

Re: 7A. 1 in the 7th edition

Posted: Mon Mar 04, 2019 5:28 pm
by Anusha 1H
you basically just have to look at the ratios of the gases they're asking for.
For a) the ratio of N2 to H2 is 1:3, so the rate N2 is consumed at would be 1/3 the rate of consumption of H2

Re: 7A. 1 in the 7th edition

Posted: Mon Mar 04, 2019 5:32 pm
by 2c_britneyly
This question is basically asking you to compare their rates, which can be determined by looking at their stoichiometric coefficients.
In this question, you're given the equation A+3B --> 2C. You know that A will be decreasing 3 times slower than B because only one mole of A is decomposing for every 3 moles of B. Logically, it makes sense that B would decompose at a rate 3 times faster than A. You can apply this logic to a reactant and product too. For every one mole of A that decomposes, it will form 2 moles of C. Therefore, the rate of formation of C is two times faster than the decomposition of one mole of A.

Re: 7A. 1 in the 7th edition

Posted: Thu Mar 07, 2019 9:19 pm
by abbydouglas1K
Basically isolate what you are looking at in the equation to the gases that the question is asking about and then set them equal to each other. If you divide the molar coefficients (what side you solve for depends on what chemical the question is asking about) and you will get the ratio of the rate of either formation or decomposition.