6th edition 15.19 part c

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Emily Tam 1k
Posts: 30
Joined: Fri Sep 28, 2018 12:22 am

6th edition 15.19 part c

Postby Emily Tam 1k » Fri Mar 15, 2019 3:08 am

In the 6th edition, there is a question asking us to solve for the value of the rate constant (k). There is a table given with all the reaction concentrations and overall rate, and we are to solve for the value K with the table. My question is why did the textbook decide to use the 4th reaction instead of the 1st reaction. Does it matter what reaction we use to solve for k?

Note: the 1st reaction had the same concentrations for [A], [B], [C] and the 4th reaction had different concentrations

timothy_ho_4B
Posts: 61
Joined: Fri Sep 28, 2018 12:29 am

Re: 6th edition 15.19 part c

Postby timothy_ho_4B » Fri Mar 15, 2019 10:03 am

It doesn't matter which reaction you use to solve for k; they all have the same rate constant.


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