Tangent

Moderators: Chem_Mod, Chem_Admin

ng1D
Posts: 43
Joined: Wed Sep 18, 2019 12:17 am

Tangent

Postby ng1D » Sun Mar 08, 2020 11:41 pm

How do we show how the instantaneous rate is obtained by drawing a tangent to the graph of concentration versus time? Is there an equation or graph we need to know?

Brian_Ho_2B
Posts: 221
Joined: Fri Aug 09, 2019 12:16 am

Re: Tangent

Postby Brian_Ho_2B » Mon Mar 09, 2020 8:35 am

The tangent line, or more importantly, its slope, is the instantaneous rate of change of the dependent variable (concentration) with respect to the independent variable (time). It's basically the concept of a derivative. The derivative is the function with respect to time that we use to calculate the instantaneous rate of change at any time. The value of that rate is the slope of the tangent line at that given time.

Sam McNeill 1E
Posts: 110
Joined: Sat Aug 24, 2019 12:17 am

Re: Tangent

Postby Sam McNeill 1E » Mon Mar 09, 2020 5:01 pm

Also, depending on the order, the slope of the linear line is equal to either -k(in 0 and 1st order) or k (in 2nd order).

ShastaB4C
Posts: 100
Joined: Thu Sep 26, 2019 12:18 am

Re: Tangent

Postby ShastaB4C » Wed Mar 11, 2020 12:14 am

You don’t usually need to find the tangent of the graph bc if you graphed they concentrations accordingly by their order, then the graph is linear so u just look in respect to its slope.


Return to “Method of Initial Rates (To Determine n and k)”

Who is online

Users browsing this forum: No registered users and 1 guest