first order of rxns
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first order of rxns
If a reaction is considered first order, does that mean that n is always 1 in first order reactions?
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Re: first order of rxns
I am pretty sure the value of n will vary, but this also confused me in the lecture on monday since I am pretty sure t=0 and ln[a]o=c but I am not sure if there is a set value for n.
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Re: first order of rxns
In class we learned that the generic form of a Differential rate Law is Rate = k[R]^n. I'm pretty sure that for first-order reactions the n in that equation will always be 1.
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Re: first order of rxns
Yes, I believe so. Since the exponent in the rate law R=k[A]^n is always the reaction order, n=1. However, for second order reactions, it's important to remember that the overall order of the reaction is the sum of the orders w/ respect to the different reactants involved in the rate determining step (long step). As a result, if we have the reactants A and B, we can have the following combinations for a second order rate law:
1) R=k[A][B]
2) R= k[A]^2
3) R=k[B]^2
1) R=k[A][B]
2) R= k[A]^2
3) R=k[B]^2
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Re: first order of rxns
If it is first order, its n value will be 1. If zero or second, n will be 0 or 2 respectively.
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Re: first order of rxns
However, for overall order of the reaction, you would add up the n, m, l values so a reaction with two first orders would have an overall order of 2.
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Re: first order of rxns
Yes, that is the definition of a first oder reaction because the n value has to be one or else it is not first order.
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Re: first order of rxns
For a reaction to be considered first order the sum of all the orders have to equal 1. It is possible that some reactants may be zero order and others be first order as together that would still total to 1. Its important to look at the orders of all the reactants to find the overall reaction order.
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Re: first order of rxns
That's correct. N is always 1 for first order reactions. In addition, it would be 2 for second order and 0 for a zero order.
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Re: first order of rxns
Yes, that is correct and if there were more than one starting chemicals the overall order must still pertain to only one.
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Re: first order of rxns
When the reaction is in first order, the value n will always be 1. When the reaction is in zero or second order, the value for n would be 0 and 2, respectively.
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Re: first order of rxns
Yes:) I would assume that n=1 for first order reactions, and similarly n=0 for zero order
hope this helps:)
hope this helps:)
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Re: first order of rxns
yes, that's correct. You can observe that a reaction is first order if n=1 and vice-versa, if n=1 you can determine that the reaction is at first-order. If n=0 or n=2, this means that the reaction is either zero-order or second-order, respectively.
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