Sapling Week 9/10 Number 3

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Phoebe Joseph
Posts: 58
Joined: Tue Nov 17, 2020 12:19 am

Sapling Week 9/10 Number 3

Postby Phoebe Joseph » Thu Mar 11, 2021 12:56 pm

Could someone please explain to me how the overall rate of the reaction relates to k in this question?
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Phoebe Joseph
Posts: 58
Joined: Tue Nov 17, 2020 12:19 am

Re: Sapling Week 9/10 Number 3

Postby Phoebe Joseph » Thu Mar 11, 2021 1:00 pm

And could someone give me a clear explanation of how the overall reaction rate relates to the reaction rate of the products?

Can Yilgor 2D
Posts: 104
Joined: Wed Sep 30, 2020 10:09 pm

Re: Sapling Week 9/10 Number 3

Postby Can Yilgor 2D » Thu Mar 11, 2021 1:10 pm

The instantaneous rate of change of [A] at a particular moment is the slope of the tangent line at that point. The slope is the rise divided by the run. To find the slope of the orange tangent line, identify two sets of coordinates on that line. One point through which it is known that the orange line crosses is t=40 s and [A]=0.35 M. Another reference point that is relatively easy to read is t=0 and [A]≈0.48 M.

Hope this helps

Phoebe Joseph
Posts: 58
Joined: Tue Nov 17, 2020 12:19 am

Re: Sapling Week 9/10 Number 3

Postby Phoebe Joseph » Thu Mar 11, 2021 1:42 pm

Yes, this helped a lot. What is the correlation between instantaneous rate of change and k? Thank you

Rajshree 1F
Posts: 108
Joined: Wed Sep 30, 2020 9:32 pm

Re: Sapling Week 9/10 Number 3

Postby Rajshree 1F » Thu Mar 11, 2021 8:06 pm

the instantaneous rate is the slope of the line tangent to the point you are focusing on. therefore u do y2-y1/x2-x1 of the orange line to get the slope of that line which is the instantaneous rate at t = 40 seconds for the blue line


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