Wk.10 #9


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Jaclyn Padilla
Posts: 19
Joined: Mon Jan 03, 2022 9:25 am

Wk.10 #9

Postby Jaclyn Padilla » Mon Mar 20, 2023 12:00 pm

The rate constant for this first‑order reaction is 0.430 s−1at 400 ∘C. A⟶products
How long, in seconds, would it take for the concentration of A
to decrease from 0.940 M
to 0.400 M?

How would I calculate this?

joselle barnoya 1k
Posts: 24
Joined: Mon Jan 09, 2023 8:37 am

Re: Wk.10 #9

Postby joselle barnoya 1k » Mon Mar 20, 2023 12:48 pm

Hello! Using the first-order equation you can solve for t ( the time it would take to decrease) by plugging in 0.940 for the initial concentration [A]0, 0.400 for the final concentration ([A]), and 0.43/s for k. From there it's very straightforward!

Damin Rawlins 3B
Posts: 23
Joined: Mon Jan 09, 2023 9:47 am

Re: Wk.10 #9

Postby Damin Rawlins 3B » Mon Mar 20, 2023 5:38 pm

To calculate the time it would take for the concentration of A to decrease from 0.940 M to 0.400 M in a first-order reaction, use
t = ln([A]0/[A]) / k
where t is the time in seconds, [A]0 is the initial concentration of A, [A] is the concentration of A after a certain amount of time, and k is the rate constant of the reaction. Substitute the values given and solve for t! :)


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