## Zero order

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

J_Rodriguez_Dis2k
Posts: 25
Joined: Fri Sep 25, 2015 3:00 am

### Zero order

if a reactant is a zero order does it effect the overall rate of the reaction?

Vishal Dobaria 4G
Posts: 17
Joined: Fri Sep 25, 2015 3:00 am

### Re: Zero order

Hello,
If there is a reactant that has a zero order, it would not have an effect on the overall order. You would essentially neglect it and add a 0 when you were summing up the orders of the reaction.

Jana Sandhu 3J
Posts: 25
Joined: Fri Sep 25, 2015 3:00 am

### Re: Zero order

The rate law for a zero order reaction is rate=k. Can also be written as rate=k[A]^0 to more plainly see that it is zero. From this you can tell that the concentration of the reactant will have no affect on the rate of the reaction, as it is solely dependent on the rate constant k.

Yasmine Choroomi 2C
Posts: 25
Joined: Fri Jul 22, 2016 3:00 am

### Re: Zero order

Also, when looking at a zero order reaction in terms of mechanisms, they are not present in the reactant portion and only the intermediates are in that portion (if you wanted to look at it from a mechanism standpoint).

Michael Lee 2I
Posts: 51
Joined: Fri Sep 29, 2017 7:05 am

### Re: Zero order

If a zero order is in the reaction, the rate law is k[A]^0 = k. Therefore it has is not based on the concentration, only the rate constant.

snehabhargava
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

### Re: Zero order

In a zero order reaction, the concentrations of the reactants does not effect the rate.