## Concept of Zero Order

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Vera Ong 3H
Posts: 26
Joined: Fri Jun 17, 2016 11:28 am

### Concept of Zero Order

Conceptually, second order is based on two molecules or atoms colliding and reacting with each other. First order would include radioactive decay of one object. What would the process be for something of zero order?

Jerry Wang 1L
Posts: 10
Joined: Fri Jul 22, 2016 3:00 am

### Re: Concept of Zero Order

A good example of 0 order is when the surface of a catalyst is saturated with the reactants (i.e all of its surface is covered by the reactant). Thus, no matter how much more you may increase the concentration of the reactants, the rate will still remain as k because those additional reactant molecules have little opportunity to interact with the surface of the catalyst. Because the rate is independent of the concentration, it fits within the definition of 0 order.

CameronJohari1J
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Joined: Fri Sep 29, 2017 7:06 am
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### Re: Concept of Zero Order

A real world example of a zero order reaction is N2O decomposing into nitrogen and oxygen with hot platinum wire as a catalyst. Once all the platinum is covered by N2O, the concentration no longer matters until new space is available.

Sohini Halder 1G
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### Re: Concept of Zero Order

mathematically it makes sense because as you do anything to the concentration, nothing changes the rate of the rxn, or 0 change.

Peri Bingham 1G
Posts: 50
Joined: Fri Sep 29, 2017 7:03 am

### Re: Concept of Zero Order

A zero order reaction is one in which the rate is independent of the reactant concentration. An example is the catalyzed decomposition of ammonia.

Alexia Joseph 2B
Posts: 56
Joined: Thu Jul 27, 2017 3:01 am

### Re: Concept of Zero Order

Another example of a zero order reaction is the decomposition of nitrous oxide to n2 gas and o2 gas.