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15.99

Posted: Tue Feb 21, 2017 9:46 pm
by Blake_Katsev_2E
Could somebody explain why graphing the half life vs. concentration of a zero order reaction is linear but not if its second order?

Re: 15.99

Posted: Tue Feb 21, 2017 10:34 pm
by Natalie Rotstein 3J
For 0 order reactions, t1/2=[A]0/2k, which means t1/2 is proportional to A, which corresponds to a linear graph. For second order, however, t1/2=1/(k[A]0), which means t1/2 is proportional to 1/A - the graph of 1/x is not linear, so therefore the second order half life graph would also be nonlinear

Re: 15.99

Posted: Tue Feb 21, 2017 10:38 pm
by Anna_Kim_2E
For second order, half life is t = 1/k[A]initial . Therefore, t (half life) and concentration have 1/[A] relationship.
Whereas, for zero order, half life t = [A]initial/2k , which shows that t(half life) and initial concentration direct linear relationship.