zero order slopes
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zero order slopes
do zero order reactions have a constant slope, a slope of zero, or a varying slope throughout the entire reaction?
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Re: zero order slopes
Since zero order reactions occur at a constant rate independent of the concentration, the rate of the reaction will not change with time or concentration as long as the reaction can continue. Therefore, the slope should be zero.
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Re: zero order slopes
Yes, slope should be zero. It's the derivative of a constant, which makes it zero.
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Re: zero order slopes
If you are graphing rate vs. time the slope will be zero, however if you are graphing [A] vs. time there will be a slope = -k
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Re: zero order slopes
Can someone explain why the slope is negative for a zero order reaction when we are plotting [A] vs. time?
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Re: zero order slopes
The graph [A] vs. time has a negative slope because the concentration of reactants (A) decreases as the reaction progresses. For zero order reactions, the concentration doesn't affect the rate and [A] = -kt + [A]initial, so the slope = -k. Also, the k value should be positive.
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