## Zero Order Reactions and Rate of Reaction

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Tasnia Haider 1E
Posts: 55
Joined: Sat Jul 22, 2017 3:01 am

### Zero Order Reactions and Rate of Reaction

When a product/reactant has a zero order, does that mean it’s concentration is independent of the rate?

Ricardo Ruiz Flores 1D
Posts: 29
Joined: Sat Jul 22, 2017 3:00 am

### Re: Zero Order Reactions and Rate of Reaction

"Independent of the rate" would mean that the concentration of that specific reactant/product does not interact with or affect the rate of the reaction; this is by definition what a zero order species does, since it is raised to the power of 0 and becomes a 1 (which does not multiply the rate constant by anything that would change it).

Chloe1K
Posts: 23
Joined: Fri Sep 29, 2017 7:05 am

### Re: Zero Order Reactions and Rate of Reaction

it means that when you change the concentration, it does not have an effect on the rate.

Charles Ang 1E
Posts: 50
Joined: Thu Jul 13, 2017 3:00 am

### Re: Zero Order Reactions and Rate of Reaction

Yes, the answers above describe it well. The way I think if it, zero order reactions aren't affected by the reaction and as a result don't change. Therefore, graphing it would be a straight line with a slope of 0.

Chris Pleman 3E
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Joined: Thu Jul 27, 2017 3:01 am
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### Re: Zero Order Reactions and Rate of Reaction

A zero order reaction also indicates that the rate of that specific reaction is at its maximum (usually due to the introduction of an enzyme) which is why changing the concentration of the reactant will not have an effect on the rate, but only the duration.

Phillip Winters 2F
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am

### Re: Zero Order Reactions and Rate of Reaction

It basically means that concentration does not affect reaction rate