## zeroth order rate

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Lauryn Jordan 1F
Posts: 76
Joined: Fri Sep 29, 2017 7:07 am

### zeroth order rate

what is the zeroth order rate? is it -k?

Jessica Nunez 1I
Posts: 58
Joined: Thu Jul 13, 2017 3:00 am

### Re: zeroth order rate

The differential rate law for the a zero-order reaction is k[A]^0 and the integrated rate law is [A] = -kt + [A]^0

Jessica Lutz 2E
Posts: 56
Joined: Fri Sep 29, 2017 7:04 am

### Re: zeroth order rate

Since rate=k[A]^0, it would make sense that the rate for a zeroth order reaction (assuming there are no other reactants) is k.

Christopher Anisi 2K
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

### Re: zeroth order rate

The rate law (rate=k[A]^0) which would mean that the rate would be equal to k.

005199302
Posts: 108
Joined: Fri Sep 28, 2018 12:15 am

### Re: zeroth order rate

Assuming that there are no other reactants, it is simply k.