## Unit for rate constant for zeroth-order reaction

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Diviya Khullar 1G
Posts: 59
Joined: Fri Sep 28, 2018 12:19 am

### Unit for rate constant for zeroth-order reaction

What is the unit for the rate constant for a zeroth-order reaction?

405161024
Posts: 36
Joined: Fri Sep 28, 2018 12:25 am

### Re: Unit for rate constant for zeroth-order reaction

I think because the rate has to be mol.L^-1.s^-1 then the rate constant has to have the same units because it's not multiplied by anything

Saman Andalib 1H
Posts: 73
Joined: Fri Sep 28, 2018 12:16 am

### Re: Unit for rate constant for zeroth-order reaction

The units for a 0th order reaction can simply be determined from setting the normal rate law units = to the rate constant times whatever reactant raised to whatever order the reaction is. For 0 order,

[mols*L^-1*s^-1]=k[A]initial^0 (0 order reaction).
This would simplify to
[mols*L^-1*s^-1]=k(1)

Therefore, the units of K in a 0 order reaction is [mols*L^-1*s^-1]