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### Zero order

Posted: Sat Mar 09, 2019 5:12 pm
What would an example of a chemical reaction equation of a zero order reaction?

### Re: Zero order

Posted: Sat Mar 09, 2019 5:25 pm

### Re: Zero order

Posted: Sat Mar 09, 2019 5:39 pm
A zero order reaction is one where the rate is independent of the concentration. An example could be the decomposition of nitrous oxide on a hot platinum wire. The rate of that reaction doesn't depend on the concentration of nitrous oxide, it depends on whether surface area runs out on the wire for decomposition to occur.

### Re: Zero order

Posted: Sat Mar 09, 2019 5:41 pm
Another example could be the evaporation of water. The rate at which liquid water becomes water vapor does not depend on a "concentration," but rather on a multitude of other things (amount of water/temperature/pressure/etc)

### Re: Zero order

Posted: Sat Mar 09, 2019 9:30 pm
A zero-order reaction is one in which the rate is independent of the concentration, we use artificial zero-order reactions to determine the order of reactants in a reaction. By supplying an excess amount of all reactants except one and then varying the concentration of the non-excess reactant to find its order.

### Re: Zero order

Posted: Wed Mar 13, 2019 10:14 pm
A zero order reaction does not change if the concentration of the reactants change. It is only based on the k. Therefore, the equation would be rate=k.

However, first order reactions do depend on the concentration of reactants and it's equation will be rate =k[A]. When the concentration of reactant A changes, the rate changes as well.

Third order reactions are dependent on the reactants squared. So it's reaction equation would be rate=k[A]^2 and when [A] changes, squared, rate will change and be squared too.

### Re: Zero order

Posted: Thu Mar 14, 2019 1:40 am
so if I'm understanding this correctly... zero orders are just equal to the constant (k). how would we write them in the k[A][B]^2 thing or would be leave them out?

### Re: Zero order

Posted: Thu Mar 14, 2019 2:30 am
Ethan Breaux 2F wrote:so if I'm understanding this correctly... zero orders are just equal to the constant (k). how would we write them in the k[A][B]^2 thing or would be leave them out?

Well, for a zero order reaction, since the rate law is fully independent of the concentration of the reactant, the rate law equation would just be the rate constant (k). There would be no concentration of the reactant in the equation.

### Re: Zero order

Posted: Thu Mar 14, 2019 10:04 am
Zero-order: a rxn for which the rate is independent of concentration of the reactant (Rate= k x (concentration)0 = k)

### Re: Zero order

Posted: Thu Mar 14, 2019 10:31 am
Correct, for a 0 order reaction, the reactant's concentration that is zero order would be left out

### Re: Zero order

Posted: Thu Mar 14, 2019 10:32 am
The order of the reaction just shows if the rate of the reaction is dependent on the concentrations. Thus, if one reactant is zero order, that means the concentration of that reactant does not affect the rate of reaction.