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Because third order reactions are so uncommon, I think Lavelle mentioned that we would not be focusing on them at all for calculations. Especially because the equation is not on the formula sheet, I think it would be really unlikely we would have to calculate anything for them. If anything, I would just understand that if it is third order, that means 3 molecules/atoms would have to collide at the same time and place in order for the reaction to occur.
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