## Half life of zero order runs

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Joseph Saba
Posts: 154
Joined: Thu Jul 11, 2019 12:16 am

### Half life of zero order runs

Why is it when you plot the half-life against [A] for a reaction that is zero order, that the plot is linear?
Also, why is the initial rate of a 1st order rxn vs [A] linear?

Ariana Iranmahboub1G
Posts: 114
Joined: Fri Aug 09, 2019 12:17 am

### Re: Half life of zero order runs

For a zero order reaction, the rate is equal to k, so it is independent from [A]. For this reason, why we plot [A] over time, the graph is linear with a slop of negative k.

Sydney Myers 4I
Posts: 100
Joined: Fri Aug 09, 2019 12:17 am

### Re: Half life of zero order runs

The concentration of A over time changes at a constant rate, k. K is not affected by anything as time goes on, which is why it's a straight line.

Shrayes Raman
Posts: 129
Joined: Sat Jul 20, 2019 12:15 am

### Re: Half life of zero order runs

Plot is linear because reaction rate is constant so linear relationship.