## 7A.15A

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Savannah Mance 4G
Posts: 107
Joined: Fri Aug 30, 2019 12:17 am

### 7A.15A

Do we know that the order of the reactant C is zero because when experiment 1 is compared to experiment 4, the increase in reactants does not influence the rate?

Betania Hernandez 2E
Posts: 107
Joined: Fri Aug 02, 2019 12:15 am

### Re: 7A.15A

Yes, that is correct.

asannajust_1J
Posts: 105
Joined: Wed Sep 11, 2019 12:16 am
Been upvoted: 1 time

### Re: 7A.15A

the ratio of the rates is one and when you change the concentrations the only exponent that will also give 1 as a result would be zero.

Osvaldo SanchezF -1H
Posts: 122
Joined: Wed Sep 18, 2019 12:21 am

### Re: 7A.15A

Well the solution is is that it must equal 1 so that means that the only value that will yield you 1 is if you put 0 as the exponent and therefore the order is 0 and does not play a role in finding the order of the other reactions. Any value to the power of 0 is 1.