## 0 order

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Sophia Dinh 1D
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

### 0 order

How do you recognize that something is zero order?

Gerald Bernal1I
Posts: 102
Joined: Thu Jul 11, 2019 12:16 am

### Re: 0 order

If the graph of [A] v. time is a negative slope straight line. Other than that you find the order of a reaction through experimental data. Zero orders do not affect the reaction rate and therefore Rate=k.

Catherine Daye 1L
Posts: 104
Joined: Wed Sep 11, 2019 12:16 am

### Re: 0 order

That is when a reaction rate only depends on k. So, if you’re given a table of different concentrations and k’s, you would see that a change in concentration doesn’t change k.

Vuong_2F
Posts: 90
Joined: Sat Sep 14, 2019 12:17 am

### Re: 0 order

0 order indicates that the rate of reaction is independent of the concentration of the reactants

Tauhid Islam- 1H
Posts: 64
Joined: Fri Aug 02, 2019 12:15 am

### Re: 0 order

A zeroth order reaction is when the rate of the reaction is not dependent on the concentration of the reactants. If the concentrations of the reacts increased or decreased, the rat of the reaction would remain the same. This is clearly seen in the graph where concentration of reactants are graphed over time and the relationship is a line with a negative slope. The slope of that line is the rate of the reaction or how quickly the reactants are decreasing per unit of time.

Ayushi2011
Posts: 101
Joined: Wed Feb 27, 2019 12:17 am

### Re: 0 order

It is independent of the concentration of the reactants.

Owen-Koetters-4I
Posts: 50
Joined: Fri Sep 28, 2018 12:16 am

### Re: 0 order

a reaction is zero order if it is independent of the concentration of reactants