q. 6

[Monica Soliman 3F]

can someone explain the zero-order x versus t graph?

[Melody Haratian 2J]

Hello, for the zero order [X] vs t graph, the rate is constant and not affected by concentration. The rate = k, and since the rate of change of [X] is constant and never changes, it will show as a straight line plot verses time. The plot is decreasing since the reactants decrease as they become products.

[Kamille Kibria 2A]

[reactants] decrease over time, so both plots of [X] vs t should have a negative slope and [products] increase over time so [Y] should have a positive slope.
for a 1st order rxn (rate = k[X]) and 2nd order (rate = k[X]^2) X is being used up in the rxn, the rate is gonna continually decreasing thru the rxn. but the amount of X being used up at some time, t, would be different than at a different time, which results in a curved line.

for a zero order rxn (rate = k) the rate of change of [X] or [Y] would be constant, meaning the amount of reactants being used up (or products being formed) is the same for all times. this results in a straight line graph.

[Asia Yamada 2B]

The [X] vs t graph is a decreasing linear graph because X is a reactant which means that its concentration decreases as the reaction progresses.