graph for 1st, 2nd, and zero order reactions


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Uyenvy Nguyen 1D
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Joined: Wed Sep 30, 2020 9:36 pm

graph for 1st, 2nd, and zero order reactions

Postby Uyenvy Nguyen 1D » Sun Mar 07, 2021 1:42 am

What would the graphs for the 1st, 2nd, and zero order reactions look like?

Khoa Vu 3l
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Re: graph for 1st, 2nd, and zero order reactions

Postby Khoa Vu 3l » Sun Mar 07, 2021 1:54 am

In order to find out whether or not a reactant is zero, first, or second-order based on experimentally derived data, you would have to plot different values against time to see which one most strongly resembles a straight or linear line. For a reactant to be considered zero-order, plotting its concentration against time ([A] vs t) should result in a decreasing linear line. For a reactant to be considered first order, plotting the natural log against time (ln([A]) vs t) should result in a decreasing linear line. Finally, for a reactant to be considered second-order, plotting the inverse of its concentration (1/[A] vs t) should result in an increasing linear line.

Taylor Newville 1C
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Re: graph for 1st, 2nd, and zero order reactions

Postby Taylor Newville 1C » Sun Mar 07, 2021 2:04 am

A zero order reaction will have a linear plot (straight line) when you plot [A] versus time.
First order will have a linear graph when you plot ln[A] versus time.
Second order will have a linear graph when you plot 1/[A] versus time (this will have a positive slope unlike the rest).

[A] is the concentration of the reactant.

Melissa Solis 1H
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Re: graph for 1st, 2nd, and zero order reactions

Postby Melissa Solis 1H » Sun Mar 07, 2021 2:41 am

From Friday's lecture, here's a visual of the graphs Dr. Lavelle drew on the whiteboard : hope this helps :)
Attachments
Screen Shot 2021-03-07 at 2.40.09 AM.png
Graphs for 1,2,&0 Order RXNs

Chinyere Okeke 2J
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Re: graph for 1st, 2nd, and zero order reactions

Postby Chinyere Okeke 2J » Sun Mar 07, 2021 4:37 pm

The graph of a zero-order reaction would be linear with a negative slope, this is because the rate law is: rate = -k[A]

The graph of a first-order reaction would be linear with a negative slope, this is because the rate law is: rate = -kln[A]
- for a natural log, the smaller the concentration the faster the rate so it makes sense that the slope is negative

The graph of a second-order reaction would be linear with a positive slope, this is because the rate law is: rate = k/[A]
- since the concentration of the reactant is on the denominator

Uyenvy Nguyen 1D
Posts: 126
Joined: Wed Sep 30, 2020 9:36 pm

Re: graph for 1st, 2nd, and zero order reactions

Postby Uyenvy Nguyen 1D » Sun Mar 07, 2021 6:27 pm

Thank you!

AndrewNguyen_2H
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Joined: Wed Sep 30, 2020 9:59 pm

Re: graph for 1st, 2nd, and zero order reactions

Postby AndrewNguyen_2H » Sun Mar 07, 2021 6:29 pm

Different functions graphed will give a linear curve. From this, you can determine what order the reaction is.

Sofia Lombardo 2C
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Re: graph for 1st, 2nd, and zero order reactions

Postby Sofia Lombardo 2C » Sun Mar 07, 2021 10:01 pm

To figure out the order, you would have to plot the data against time and figure out which is the most linear. A zero order reaction would be linear with a negative slope. A first order reaction would be linear with a negative slope. A second order reaction would be linear with a positive slope.

DominicMalilay 1F
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Re: graph for 1st, 2nd, and zero order reactions

Postby DominicMalilay 1F » Sun Mar 07, 2021 11:10 pm

Like some of the other replies here, the first and zero order reactions have negative slopes, but the second order reaction has a positive slope! Hope this helps


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