Sapling #4 (week 9/10) [ENDORSED]
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Sapling #4 (week 9/10)
For question 4, can someone help me identify the proper units? I don't know which ones I got right and which ones I got wrong :(
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Re: Sapling #4 (week 9/10)
Hello! I can help with this one.
One of the units is not used. This threw me off too, at first, so make sure to leave M^2/s in the answer bank, since it is not the correct unit for any of the reactions. Try again with the remaining four and if you are still stuck, I can help help you!
One of the units is not used. This threw me off too, at first, so make sure to leave M^2/s in the answer bank, since it is not the correct unit for any of the reactions. Try again with the remaining four and if you are still stuck, I can help help you!
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Re: Sapling #4 (week 9/10)
If you're not sure which is which, it might be helpful to write out the equation and solve using units. so like for first order- rate=k[A] would be M/s = k*M, and solving for k would leave 1/s, because the Ms would cancel.
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Re: Sapling #4 (week 9/10)
I also tried multiple times trying to figure out this one. I did not notice that M^2/s should stay in the answer box since it is neither one of them. Ultimately I figured out this question by writing out the formulas for each order reaction and then figure out the expression of k and thus the proper units:
zero order: rate = k M/s = k
first order: rate = k[A]. M/s = kM M/Ms = k and thus 1/s =k
second order: rate = k[A]^2 M/s=kM^2 M/s M^2 =k and thus 1/s M = k
third order: rate=k[A]^3 M/s=kM^3 M/s M^3 =k and thus 1/s M^2 =k
zero order: rate = k M/s = k
first order: rate = k[A]. M/s = kM M/Ms = k and thus 1/s =k
second order: rate = k[A]^2 M/s=kM^2 M/s M^2 =k and thus 1/s M = k
third order: rate=k[A]^3 M/s=kM^3 M/s M^3 =k and thus 1/s M^2 =k
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