## Integrated rate laws

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Gabrielle Schwab 1G
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Joined: Fri Sep 25, 2015 3:00 am

### Integrated rate laws

For 15.29, do you switch the initial concentration of A with the concentration of A at time t in the first order rate law equation because the question is asking for the reaction expressed as the rate of loss of A?

Chem_Mod
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### Re: Integrated rate laws

The integrated rate law is just the rate of loss of A that has been integrated

ln [A] = -kt + ln [A]0