Posted: Sun Feb 19, 2017 4:33 am
Why is the half-life of a first order reaction independent of the initial concentration?
Re: Half Life
Posted: Sun Feb 19, 2017 12:32 pm
When you look at the 1st order integrated rate law, you see that ln[A]=-kt+ln[A]o. At the half life, [A]=1/2 of [A]o. When you plug this value into the equation, you will get ln(1/2([A]o/[A]o)). The [A]o values cancel so you are left with simply ln 1/2. This is why the half life is independent of [A]o.