15.37


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Rucha Kulkarni 2A
Posts: 43
Joined: Fri Sep 29, 2017 7:05 am

15.37

Postby Rucha Kulkarni 2A » Sun Feb 25, 2018 10:36 pm

Does anyone know how to solve exercise 15.37?

Mia Navarro 1D
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.37

Postby Mia Navarro 1D » Sun Feb 25, 2018 10:56 pm

I’m not sure how to do all of it, but use the rule of 70 for part (a).

torieoishi1A
Posts: 32
Joined: Sat Jul 22, 2017 3:00 am

Re: 15.37

Postby torieoishi1A » Wed Feb 28, 2018 8:12 pm

(a)t1/2=.693/k=.693/2.81 x 10^-3 min^-1=247 min
(b) t=(ln([so2cl2]"sub0"/[So2Cl2]"subt")/k=ln10/(2.81 x 10^-3 min^-3)=819 min
(c)[A]"subt"=[A]"sub0"e^-kt // masses and concentrations are proportional (b/c the vessel is sealed), therefore (mass left)"subt"=(mass)"sub0"e^-kt
14g x e^ (-2.81x10^-3min^-1 x 60min/h x 1.5h) = 10.9 g


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