15.23 (c)

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Sabrina Dunbar 1I
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15.23 (c)

Postby Sabrina Dunbar 1I » Tue Feb 27, 2018 12:20 pm

Can someone explain to me how we incorporate the coefficient of 2 from the reactant A into figuring out k? I got the correct answer for parts (a) and (b), but I am lost on which equation to use for part (c). Any guidance would be greatly appreciated!

Emily Duggan 1F
Posts: 42
Joined: Fri Sep 29, 2017 7:07 am

Re: 15.23 (c)

Postby Emily Duggan 1F » Tue Feb 27, 2018 2:28 pm

Because the overall reaction is different (2A -> B + C vs the previous A -> B), you have to calculate [A]t. Since [A]t is concentration of A, you incorporate the coefficient here to 'cancel' mol B.
[A]t = [A]0 - [(2 mol A/1 mol B)(.034 mol B/L)] You can see, the mol B cancel so the calculation for [A]t is only comprised of mol A/L.
Hope this helps!

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