problem 15.23B


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Amy Zheng 2l
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Joined: Fri Sep 29, 2017 7:04 am

problem 15.23B

Postby Amy Zheng 2l » Thu Mar 01, 2018 11:59 pm

For part B,how come we use In(Ainitial/Afinal)=kt? shouldn't it be -kt?

Anna Goldberg 2I
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Re: problem 15.23B

Postby Anna Goldberg 2I » Fri Mar 02, 2018 12:17 am

ln(At)/(Ainitial)=-kt

When you do ln(A initial)/(At), the swap of the numerator and denominator makes ln(A initial)/(At)=kt

Hena Sihota 1L
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Re: problem 15.23B

Postby Hena Sihota 1L » Fri Mar 02, 2018 1:09 am

ln[A]t-ln[A]0=-kt If you divide both sides of this equation by -1 then you get -[A]t+[A]0=kt which can be rewritten as [A]0-[A]t=kt. According to log rules, this equation can be rewritten as ln[A]0/ln[A]t=kt

Rohan Chaudhari- 1K
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Joined: Fri Sep 29, 2017 7:06 am

Re: problem 15.23B

Postby Rohan Chaudhari- 1K » Sat Mar 03, 2018 4:49 pm

You can also just use [A]=[A]initial * e^-kt, which is just a simplified verision of the ln[A]=-kt+ln[A]initial equation


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