Page 1 of 1

15.23

Posted: Sun Mar 04, 2018 7:32 am
by donnanguyen1d
For Part C, why did you have to subtract (2(.034molB)) from (.153 molA) to get [A]t, I thought calculating [A]t would only require multiplying .034molB by 2?

Re: 15.23

Posted: Sun Mar 04, 2018 7:43 am
by Deborah Cheng 1F
I believe it's because the equation of the reaction given is 2A B + C so we need to account for the ratio of 2 mol A used to 1 mol B produced.

Re: 15.23

Posted: Sun Mar 04, 2018 11:04 am
by Samira 2B
It is because that accounts for the change in reactants going to products. Since, products is produce that means the reactants must be reduced. So, you would subtract the 0.068 from the initial reactant concentration.

Re: 15.23

Posted: Sun Mar 04, 2018 11:16 am
by ConnorThomas2E
You start with the initial concentration of A, and you need to find how much b is produced to see how much the concentration of A decreases. Therefore, you would subtract 2*b from the initial concentration of A

Re: 15.23

Posted: Sun Mar 04, 2018 9:28 pm
by Kyra LeRoy 1E
For product to form, there must be something taken from the reactant. Therefore, you take the initial concentration of A and subtract the concentration that has been used to create B at time t.