$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Emily Duggan 1F
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Joined: Fri Sep 29, 2017 7:07 am

Is radioactive decay a first order reaction? If so, why?

Ozhen Atoyan 1F
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Radioactive decay is a first order reaction because the decay rate is proportional to the first power of radioactive atoms present. Therefore, this matches with first order kinetics.

Christy Lee 2H
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Does this mean that radioactive decay only works for a reaction if there's one reactant since it's a first order reaction?

Nehal Banik
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Joined: Thu Jul 13, 2017 3:00 am

Not sure, one of the reactants can be zero order, or it can be a slow step where on of the reactants doesn't necessarily affect the rate.

Harjas Sabharwal 1G
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