15.37(B) homework


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Jack Papciak 2F
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Joined: Fri Sep 29, 2017 7:06 am

15.37(B) homework

Postby Jack Papciak 2F » Tue Mar 06, 2018 11:59 pm

I couldn't figure out this question so I checked the solutions manual and it says eventually you get ln10/2.8x10^-3. I don't understand where the ln10 is coming from. Any help would be appreciated

Joshua Xian 1D
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Re: 15.37(B) homework

Postby Joshua Xian 1D » Wed Mar 07, 2018 11:04 am

Since final concentration is 10% of the initial, dividing initial by final would result in 10. Therefore, you get ln(10)/k.

Shanmitha Arun 1L
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Re: 15.37(B) homework

Postby Shanmitha Arun 1L » Wed Mar 07, 2018 11:51 am

For problems like this that give % of the initial like 10%, it would be ln(1/0.1) which ends up being ln(10). For 15%, it would be ln(1/0.15) since its ln of [A]/[Ao]

Sophie 1I
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Re: 15.37(B) homework

Postby Sophie 1I » Wed Mar 07, 2018 4:23 pm

So then it wouldn't matter whether you had the actual initial concentration?


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