## unique rate [ENDORSED]

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Belle Calforda3f
Posts: 67
Joined: Fri Sep 29, 2017 7:07 am

### unique rate

what is a unique rate and how do you find it?

Chem_Mod
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### Re: unique rate  [ENDORSED]

For example:

2A + 3B -> C

The unique rates are scaled by the stoichiometric coefficients so they are all equal.

-(1/2)d[A]/dt = -(1/3)d[A]/dt = +d[C]/dt

This way you don't always have to report a rate of reaction with respect to a particular component. You can simply report the unique rate.