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k' in Pseudo-First-Order Rate Laws

Posted: Fri Mar 09, 2018 4:15 pm
by Clarisse Wikstrom 1H
Why is k' used in the pseudo-first-order rate law? Doesn't k' mean the rate constant for the reverse reaction? Thanks!

Re: k' in Pseudo-First-Order Rate Laws

Posted: Fri Mar 09, 2018 4:24 pm
by Mitch Walters
k' just means a different rate constant. This is because we are treating a second order reaction as if it's a first order reaction, so it must have a different rate constant.

Re: k' in Pseudo-First-Order Rate Laws

Posted: Tue Mar 13, 2018 9:25 pm
by Daniisaacson2F
Yes, k prime if the reverse reaction's rate constant. You can use that and the forward reaction's k to figure out the equilibrium constant, K.

Re: k' in Pseudo-First-Order Rate Laws

Posted: Sun Mar 18, 2018 10:44 am
by Akash_Kapoor_1L
How do we know when to use a pseudo-first-order method instead of calculating the second order rate law normally?

Re: k' in Pseudo-First-Order Rate Laws

Posted: Sun Mar 18, 2018 6:17 pm
by Christina Bedrosian 1B
k' stands for k*the reactants that you don't use in the rate law