slope

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

TarynLane2J
Posts: 30
Joined: Sat Jul 22, 2017 3:00 am

slope

What is the slope of the linear plot of a first order reaction?

Masih Tazhibi 2I
Posts: 33
Joined: Fri Sep 29, 2017 7:06 am

Re: slope

The slope of the first order reaction can be found through assessing the integrated rate law. The first order integrated rate law is ln(A)=-kt+ln(Ao), which is in the linear y=mx+b form. As such, the slope is -k.

Shawn Patel 1I
Posts: 54
Joined: Thu Jul 27, 2017 3:01 am

Re: slope

Hey,
The slope of the graph is -k. The graph is baed on ln(a) against time.

RussellChin_3A
Posts: 42
Joined: Sat Jul 22, 2017 3:01 am

Re: slope

When you say linear plot of a first order reaction you are refering to the graph that results from a plot of ln[A] and time which results in a negative slope. However, if you were to graph [A] vs. time without the ln, you would not get a linear plot, instead a plot of exponential decay