## Integrated Rate Laws

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Anika_Patel_1G
Posts: 32
Joined: Fri Sep 29, 2017 7:06 am

### Integrated Rate Laws

Whenever we use the integrated rate law formulas, are we assuming that it is for a reaction with only one reactant? Or are using the equation with respect to one reactant in the reaction?

Matthew 1C
Posts: 47
Joined: Fri Sep 29, 2017 7:06 am

### Re: Integrated Rate Laws

with 1st order reactions there is only one reactant but for 2nd order reactions there can be two first order reactants but I think most of the time we will use reactions with one 2nd order reactant because that uses the 2nd order integrated rate law found on the formula sheet of the test

Sarah Maraach 2K
Posts: 31
Joined: Thu Jul 27, 2017 3:00 am

### Re: Integrated Rate Laws

Yes most of the time you will probably only encounter second order reactions with only one reactant counted in the rate equation.

Helen Shi 1J
Posts: 78
Joined: Sat Jul 22, 2017 3:00 am

### Re: Integrated Rate Laws

Can we only find the concentration of reactants with integrated rate laws, or is the reverse law applicable to the concentration of products?

Wenxin Fan 1J
Posts: 53
Joined: Thu Jul 13, 2017 3:00 am

### Re: Integrated Rate Laws

Integrated rate laws applies to reactions other than first order reactions as well. The ln[A] vs t, 1/[A] vs T are both from integrated rate laws.