How to calculate [A]t in 7B.3 7th ed

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How to calculate [A]t in 7B.3 7th ed

Postby JulieAljamal1E » Tue Mar 05, 2019 6:04 pm

In part C, we’re asked to calculate the rate constant for the rate loss of A from 2A->B+C given that [A]0=0.153 mol/L and that after 115s give the the concentration of B rises to 0.034 mol/L. To do this, I know we have to uses ln([A]t/[A]0)=-kt. But first we need to come of with [A]t. The solutions shows that [A]t=(0.153molA/L)-[(2molA/1molB)(0.034molB/L)=0.085. I dont understand why we have to subtract (2/1)(.034) from 0.153. That makes it seem like we’re calculating the change in concentration of A. Why is [A]t not just (2molA/1molB)(0.034molB/L)??

Shubham Rai 2C
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Re: How to calculate [A]t in 7B.3 7th ed

Postby Shubham Rai 2C » Tue Mar 05, 2019 7:07 pm

What you are doing is finding the leftover [A] because if you just do (2molA/1molB)(0.034molB/L), it gives you the change in [A] based on how much the [B] changed. That's why you have to subtract the change from the initial to get the [A]t.

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