## Half-Life

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Jessica Tsui 1H
Posts: 30
Joined: Fri Sep 28, 2018 12:21 am

### Half-Life

Why is the half-life for first order reaction the only one that is independent of initial [A]?

Posts: 77
Joined: Fri Sep 28, 2018 12:28 am
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### Re: Half-Life

The initial concentration just cancel each other out when the half life equation is being derived
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chaggard
Posts: 37
Joined: Fri Sep 28, 2018 12:19 am

### Re: Half-Life

This can be visually shown on a graph because in first order reaction, the time in-between one half reaction and the next is the exact same, the only thing changing would be the slope, or K.